Question

please it's urgent do it fast

Answer 1

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Answer 2

$4x = \csc( \alpha ) \\ \frac{8}{x} = \cot( \alpha ) \\ 16 {x}^{2} = { \csc( \alpha ) }^{2} \\ \frac{64}{ {x}^{2} } = { \cot( \alpha ) }^{2} \\ 16( {x}^{2} - \frac{4}{ {x}^{2} } ) = 1 \\ {x}^{2} - \frac{4}{ {x}^{2} } = \frac{1}{16}$
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