Question

please.......... jaldi...​

Answer 1

Hey mate!

Here's your answer!!

Let the sum lent at 8% is x, then sum lent at 10% is (10000 - x)

x \times \frac{8}{100} \times 1 + (10000 - x) \times \frac{10}{100} \times 1x×

100

8

×1+(10000−x)×

100

10

×1

= 10000 \times \frac{92}{100} \times 1=10000×

100

92

×1

= \frac{8x}{100} + \frac{10(10000 - x}{100} = 920=

100

8x

+

100

10(10000−x

=920

8x + 100000 - 10x = 92000

➡ -2x + 100000 = 92000

➡ -2x = 92000 - 100000

➡ -2x = -8000

➡ x = 4000

Amount lent at 8% = ₹4000

Amount lent at 10% = (10000 - 4000) = ₹6000

hope \: it \: helps \: you.hopeithelpsyou.

✌ ✌

#BE BRAINLY

Answer 2

Answer:

Rs. 4000, Rs. 6000

Step-by-step explanation:

$\frac{total \: intrest \: \times }{total \: sum} = average \: yearly \: interest$

$⇒ \: total \: intrest \: = \frac{9.2 \times 10000}{100} = rs. \: 920$

$Let \: the \: sum \: lent \: at \: 8\% \: p.a. \: \\ be \: Rs. \: x. </p><p>$

$Then, \: the \: sum \: lent \: at \: 10\% \\ p.a. \: is \: Rs. \: (10000−x)$

$∴ \: \frac{x \times 8 \times 1}{100} + (10000 - x) \times \: 10 \times 1 = 920$

$⇒ \frac{8 \times }{100} + 1000 - \frac{10 \times }{100} = 920$

$⇒ \frac{2 \times }{100} = 80$

$⇒ \times = 4000$

$Therefore, \: the \: two \: partsare \\ Rs. 4000 \: and \: Rs. \: 6000$