Question

please keep me solution sums please please ​

Answer 1

Answer:

OK check your answer please

Answer 2

Answer:

Given : oq is the bisector of ∠AOC , OP is the bisector of ∠BOC , ∠AOC=60°

∠BOC + ∠AOC = 180° (LINEAR PAIR)

∠BOC + 60° = 180°

∠BOC = 180° - 60°

∠BOC = 120°

∠POQ + ∠QOA = 180° (Linear pair)

∠POQ +30 = 180 (∠QOA is 30° because OQ is the bisector of ∠AOC)

∠POQ = 180° - 30°

∠POQ = 150°