please koi 47th question ka answer kro fast in detail
Answers
Answer:
(0,7/3) , (7,0) , (1,2)
Step-by-step explanation:
x + 3y = 7
x=0,y=7/3 {0,7/3}
x + 3y = 7
0 + 3(7/3) = 7
3(7/3) = 7
7= 7
7,0 [ x=7 , y=0 ]
x + 3y = 7
x + 3y
7 + 3(0)
7 + 0
7
1,2 [ x=1 , y=2 ]
x + 3y
1 + 3(2)
1 + 3*2
1 + 6
7= 7
Solution :-
checking all given options we get,
(a) (2, 5)
→ x + 3y = 7
→ 2 + 3*5 = 7
→ 2 + 15 = 7
→ 17 ≠ 7
Not a solution of given equation .
(b) (0, 7/3)
→ x + 3y = 7
→ 0 + 3*(7/3) = 7
→ 0 + 7 = 7
→ 7 = 7
It is a solution of given equation .
(c) (3, 1)
→ x + 3y = 7
→ 3 + 3*1 = 7
→ 3 + 3 = 7
→ 6 ≠ 7
Not a solution of given equation .
(d) (7, 0)
→ x + 3y = 7
→ 7 + 3*0 = 7
→ 7 + 0 = 7
→ 7 = 7
It is a solution of given equation .
(e) (0, 7)
→ x + 3y = 7
→ 0 + 3*7 = 7
→ 0 + 21 = 7
→ 21 ≠ 7
Not a solution of given equation .
(f) (1, 2)
→ x + 3y = 7
→ 1 + 3*2 = 7
→ 1 + 6 = 7
→ 7 = 7
It is a solution of given equation .
Therefore, the solutions of x + 3y = 7 are :-
- (b) (0, 7/3)
- (d) (7, 0)
- (f) (1, 2)
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