Prove that : (a+b)^-1 (a^-1+b^-1)= 1/ab
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Multiply both sides by A+B on the right, to get
I=A−1(A+B)+B−1(A+B)=I+A−1B+B−1A+I
and so
A−1B=−B−1A−I
Multiplying by B on the left, we get BA−1B=−A−B .
If we multiply by A+B on the left we get
I=(A+B)A−1+(A+B)B−1=I+BA−1+AB−1+I
and so
AB−1=−BA−1−I
Multiplying by A on the right, we obtain
AB−1A=−B−A
Since −B−A=−A−B , we conclude
AB−1A=BA−1B=−(A+B)
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