Question

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Answer 1

Step-by-step explanation:

Given,

$6 \div 3 \sqrt{2} - 2 \sqrt{3} = 3 \sqrt{2} - a \sqrt{3}$

To find:

the value of

$a$

Solution:

$6 \div 3 \sqrt{2} - 2 \sqrt{3} = 3 \sqrt{2} - a \sqrt{3}$

$6 = 3 \sqrt{2} - a \sqrt{3} \times 3 \sqrt{2} - 2 \sqrt{3} = 6 = 9( { \sqrt{2)} }^{2} - 6 \sqrt{5} - 3a \sqrt{5} - 2a( { \sqrt{3)} }^{2} = 6 = 18 - 6 \sqrt{5} - 3a \sqrt{5} - 6a = 6 = 18 - 11a \sqrt{5} - 6a = 6 = 18 - 17a \sqrt{5} =$

$18 - 17a \sqrt{5} = 6 - 18$

$17a \sqrt{5} = 6 - 18 = 17a \sqrt{5} = - 12$

$a \sqrt{5} = - 12 \div - 17$

$a = - 12 \div - 17 \div \sqrt{5} = a = - 12 \div 1 \times \sqrt{5} \div - 17 = a = - 12 \sqrt{5} \div - 17$

Answer:

-12_/5/-17

Answer 2

Answer:

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Step-by-step explanation:

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