Question

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Answer 1

Answer:

Step-by-step explanation:

Given,

Sum of zeroes (α+β) = 2

Product of zeroes (αβ) = -3/5

We know that,

$y^{2} -(\alpha +\beta )y+\alpha \beta$

So,

$y^{2} -(2)y+(-3/5)\\y^{2} -2y-3/5\\5y^{2} -2y-3$