Question

please make it fast it's very urgent please​

Answer 1

Answer:

Quotient : 3x - 10 Remainder : 40x

Step-by-step explanation:

*Note : This is a division using fraction.

$\frac{6x^3-54x^2+120x}{2x^2-8x}$

$=\frac{3x(2x^2-8x+8x)-54x^2+120x}{2x^2-8x}$ ⇒ Eliminating The Highest Degree Term

$=\frac{3x(2x^2-8x)+24x^2-54x^2+120x}{2x^2-8x}$ ⇒ Pulling +8x Out

$=3x+\frac{-20x^2+120x}{2x^2-8x}$ ⇒ Eliminating The Highest Degree Term, Quotient 3x

$=3x+\frac{-10(2x^2-8x+8x)+120x}{2x^2-8x}$ ⇒ Pulling +8x Out

$=3x-10+\frac{-80x+120x}{2x^2-8x}$ ⇒ Simplifying The Remainder, Quotient 3x - 10

$=3x-10+\frac{40x}{2x^2-8x}$ ⇒ End Of Division

Quotient $3x-10$, Remainder $40x$