Question

please . my final exams are approaching. god will bless you. pls help ​

Answer 1

Join OA,OC and OB.

Clearly, ∠OCA is the angle in a semi-circle.

∴ ∠OCA=90°

In right triangles OCA and OCB, we have

OA=OB=r

∠OCA=∠OCB=90° and, OC=OC

So, by RHS−criterion of congruence, we get

△OCA≅△OCB

∴AC=CB

Hope this'll help you.