Question

please only need correct answer the first right answer will be mark brilliant and wrong answer will be report all right answer giver will get 20 likes
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Answer 1

Answer:

Let the cost of fare be Rs.′x′ and the reservation charge be Rs.′y′.

By condition I:x+y=216                    ....(i)

By condition II:

one full and one half ticket =1+21=23

cost of half railway ticket is =2x

∴,x+y+2x+y=327

⇒23x+2y=327   

⇒3x+4y=654            ....(ii)(after multiplying by 2 )

By solving (i) and (ii) we will get

3x+4y−4x−4y=654−864

∴x=210 and put x=210 in (i) we get y=216−x=216−210=6

∴y=6

Hence, basic fare for one ticket is Rs.210 and reservation fare is Rs.6

Step-by-step explanation:

Please mark as brainlist

Hope this helps...

Answer 2

Answer:

༺AnsWer༻

Step-by-step explanation:

sorry mate your question is not clear