Question

PLEASE PLEASE ANWER IT'S URGENT!

Q6. A train starting from rest attains a velocity of 72 km/hr in 5 minutes. Assuming

that the acceleration is uniform find

a) The acceleration

b) The distance travelled by the train
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Answer 1

Answer:

a. sinnce train start for rest u=0

v=72km/h= 20m/sec

t= 5min= 300 sec

a= (v-u)/t

a= (20-0)/300

a= 1/15 m/sec^2

b. speed= 20m/sec

time = 300 sec

distance= speed×time

distance = 20×300

distance= 6000 m

or

distance = 6km

*Hope U understand it*