Question

please please give me answer fast. please right answers dena



6th question vala ​

Answer 1

Step-by-step explanation:

The smallest and the largest numbers of three digits, which are divisible by 5 are 100 and 995 respectively,

So, the sequence of three digits numbers which are divisible by 5 is 100,105,110,...,995.

It is an AP with first term a=100 and common difference d=5.

Let there be n terms in this sequence. Then,

a

n

=995⇒a+(n−1)d

995=100+(n−1)×5

⇒n−1=179

⇒n=180