Math, asked by abhishek21012007, 9 months ago

please please help and please don't try to it by yourself it is easy I don't know the answer that's why I am asking please solve it​

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Answers

Answered by Msaikrishna2005
1

Answer:

a) 2cosθ = 1

cosθ = 1/2

θ = 60°

b) √3tanθ = 1

Tanθ = 1/√3

θ = 30°

c) 2cos3θ = 1

cos3θ = 1/2

3θ = 60°

θ = 20 °

d) 2sin2θ = √3

sin2θ = √3/2

2θ = 60°

θ= 30°

e) cos θ = √3 sinθ

cosθ / sinθ = √3

tanθ = √3

θ= 60°

f) √2sin3θ = 1

sin3θ = 1/√2

3θ = 30 °

θ = 10°

g) √3 secθ = 2

secθ = 2/√3

θ = 30°

Step-by-step

explanation:please mark me as brainliest.

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