Question

please please please answer it fast.jitne sum atte hai utne he kark daldo please​

Answer 1

Step-by-step explanation:

ans 2.

y. x.

________

8. 1.

5. 0.

11. 2.

ans 3.

Given

>AC=AD

AB bisects Angle A.

:. angle CAB = angle DAB

In ∆CAB AND ∆DAB

CA=DA. (given)

Angle CAB = Angle DAB. ( given )

AB=AB (COMMON)

by SAS ∆CAB ~= ∆DAB

by CPCT BC=BD

ans 4.

as 24, 32 and 40 is an Pythagoras triplet

The angle in front of the largest side is a right angle

Hence area = 24×32=768

ansV.

ans1)

i)

F=(9/5)C +32

95F = 95[(9/5) + 32]

= 19×9 + 95×32

171 + 3,040

=3211°C

ii)

ans2)

12x + 17x + 25x =540cm

54x=540cm

x=10cm

sides are

120cm

170cm

250cm

Apply the Pythagorean theorem to the left-hand triangle getting:

h2+(250−x)2=1702 .

Apply the Pythagorean theorem to the right-hand triangle getting:

h2+x2=1202 .

Subtract the second equation from the first:

(250−x)2−x2=14500 .

Simplify:

62500−500x=14500 .

Solve for x getting:

x=96 .

Plug into the second equation above and get:

h2+962=1202 , so h2=5184=722 , so

h=72 .

now find area