Question

please please please guys!!!!!!!answer the 14th question.....

Answer 1

angleAFD =180-70 =110
angleAFD = angle CDP= 55°(CD &AF are parallel lines cut by a straight line PF)
therefore angle DFG=anglePDE= 110-55 =55°

Answer 2

THANKS FOR THE QUESTION !

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GIVEN :

=> AB PARALLEL TO CD :

=> DE PARALLEL TO FG :

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TO FIND :

=> \_ AFG

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SUPPLEMENTARY ANGLES MEASURE 180° :

SO,

=> \_ AFG + \_ GFB = 180°

=> \_ AFG + 70° = 180°

=> \_ AFG = 180° - 70°

=> \_ AFG = 110°

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TO FIND :

=> \_ AFP

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=> AB IS PARALLEL TO CD :

=> TAKE PF AS TRANSVERSAL :

=> BY THEOREM OF CORRESPONDING ANGLES :

=> \_ CDF = \_ AFD

=> 55° = \_ AFD

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=> SIDES OF THE ANGLES ARE PARALLEL

=> SO,

=> THE ANGLES ARE CONGRUENT .

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TO FIND :

=> \_ DFG

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\_ AFD + \_ DFG + \_ GFB = 180°

=> 55° + \_ DFG + 70° = 180°

=> \_ DFG = 180° - 70° - 55°

=> \_ DFG = 55°

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TO FIND :

=> \_ PDE :

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DE IS PARALLEL TO FG :

=> TAKE PF AS TRANSVERSAL :

=> BY THEOREM OF CORRESPONDING ANGLE THEOREM :

=> \_ PDE = \_ DFG

=> BUT \_ DFG = 55°

=> \_ PDE = 55°

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HOPE IT WILL HELP U ......

THANKS AGAIN ......

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