Question

please please slove the following equations

Answer 1

10) (y-4)/ 3 + 3y =4

={ (y-4) +3*3y} /3 =4

= {(y-4 +9y)} /3 = 4

= y-4 +9y = 4*3

= 10 y = 12 +4

= y = 16 / 10 = 8 /5

11) {b+(b+1)+(b+2)} /4 =21

= b+ b+1 + b+2 = 21 *4

= 3b +3. = 84

= 3b = 84 -3

= 3b =81

= b = 81 / 3 =27

hope it helps u.
mark brainliest.

Answer 2

4y-3y+4

4y-3+3=3y+4+3(add 3 to both the sides)

4y=3y+7

4y-3y=3y=7(subtract 3y from both sides)

1y=7(1y=y)