Question

please please solve it​

Answer 1

Answer:

x=√2/3, √2/3

Step-by-step explanation:

$3 {x}^{2} - 2 \sqrt{6} x + 2 \\ 3 {x}^{2} - \sqrt{6} x - \sqrt{6} x + 2 \\ \sqrt{3} x( \sqrt{3} x-\sqrt{2} )-\sqrt{2} ( \sqrt{3} x - \sqrt{2} ) \\ ( \sqrt{3} x - \sqrt{2} )( \sqrt{3}x - \sqrt{2} ) \\ अत \: समीकरण \: के \: मूल x \: के \\ वे \: मान \: है, जिनके लिए \\ ( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} ) = 0 \\ ( \sqrt{3} x - \sqrt{2}) = 0 \: \: or \: ( \sqrt{3} x - \sqrt{2}) = 0 \\ x = \sqrt{ \frac{2}{3} } \: \sqrt{ \frac{2}{3} }$

I hope this help you