Math, asked by anjalina2828, 9 months ago

please please solve it step by step​

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Answered by maheshpurohit2004
1

Answer:

Step-by-step explanation:

1. Let n+1,n+3,n+5,n+7,n+9,n+11,n+13,n+15------eq(1)  be 8 odd numbers.

then sum of these 8 odd numbers is 64

n+1+n+3+n+5+n+7+n+9+n+11+n+13+n+15=64

8n+64 = 64

8n = 64-64

n = 0

substitute n=0 in eq(1)

∴ The 8 odd numbers are 1,3,5,7,9,11,13,15

∴ 1+3+5+7+9+11+13+15=64

2. Let n+1, n+3, n+5, n+7, n+9, n+11, n+13, n+15, n+17, n+19, n+21------eq(1)  be 11 odd numbers.

then sum of these 11 odd numbers is 121

n+1+n+3+n+5+n+7+n+9+n+11+n+13+n+15+n+17+n+19+n+21=121

11n+121 = 121

11n = 121-121

n = 0

substitute n=0 in eq(1)

∴ The 11 odd numbers are 1,3,5,7,9,11,13,15,17,19,21

∴ 1+3+5+7+9+11+13+15+17+19+21=121

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