please please tell me by solving in note book
Attachments:
Answers
Answered by
0
Firstly Draw regular hexagon ABCDEF with ∆ABE inside it
All sides of hexagon are equal in length
Sum of angles of a polygon = (n - 2)180
n = number of sides
Sum of angles of a hexagon is 720°, since it is a regular hexagon each interior angle has measure 120°.
Quadrilateral ABEF contains half the angle measure of the hexagon
its interior angle measure = 360°
angle AFE = 120° (angle of hexagon ABCDEF)
In ∆ AFE is isosceles;
angle FAE = angle FEA = 30°
sum of angles of ∆ = 180°
=> angle FAE + angle EAB = 120°
=> therefor angle EAB = 90°
=> angle ABE is one half of 120° = 60°
angle ABE + angle EAB + angle AEB = 180° therfore angle AEB = 30°
All sides of hexagon are equal in length
Sum of angles of a polygon = (n - 2)180
n = number of sides
Sum of angles of a hexagon is 720°, since it is a regular hexagon each interior angle has measure 120°.
Quadrilateral ABEF contains half the angle measure of the hexagon
its interior angle measure = 360°
angle AFE = 120° (angle of hexagon ABCDEF)
In ∆ AFE is isosceles;
angle FAE = angle FEA = 30°
sum of angles of ∆ = 180°
=> angle FAE + angle EAB = 120°
=> therefor angle EAB = 90°
=> angle ABE is one half of 120° = 60°
angle ABE + angle EAB + angle AEB = 180° therfore angle AEB = 30°
Similar questions