Math, asked by Akshat0161, 5 months ago

please pls pls pls please please please pls pls please please pls pls pls please pls pls pls please please please pls pls please please pls pls plsplease pls pls pls please please please pls pls please please pls pls plsplease pls pls pls please please please pls pls please please pls pls pls SOLVE

i)
 \frac{1}{a + b + x}  =  \frac{1}{a}  +  \frac{1}{b}  +  \frac{1}{x}
ii)
x {}^{2}   + (\frac{a}{a + b}  +  \frac{a + b}{a} )  + 1 = 0

Answers

Answered by noorpreet4388
1

Answer:

Let X,Y and Z be three jointly continuous random variables with joint PDF

fXYZ(x,y,z)=⎧⎩⎨⎪⎪13(x+2y+3z)00≤x,y,z≤1otherwise

Find the joint PDF of X and Y, fXY(x,y).

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