Please proove ques. 1
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Kahali:
i think the answer is wrong
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Take 2^28 common from both Numerator & Denominator
solving numerator:
2^28(2^2 + 2+1)= 2^28(4+2+1)= 7 x 2^28
Solving Denominator:
2^28(2^3 + 2^2- 2^1)= 2^28( 8+4-2)= 10 x 2^28
On Dividing 2^28 will cancel out & 7/10 will be left
solving numerator:
2^28(2^2 + 2+1)= 2^28(4+2+1)= 7 x 2^28
Solving Denominator:
2^28(2^3 + 2^2- 2^1)= 2^28( 8+4-2)= 10 x 2^28
On Dividing 2^28 will cancel out & 7/10 will be left
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