Question

Please prove all three

Answer 1

$triangle \: acn = bxo \: congurent \: \\ therefore \: angle \: n = angle \: b \\ therefore \: cnllbo \\ an = bx \: cpct \\ ba + ax = ax + nx \: \\ therefore \: ab = nx \:$
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Answer 2

In CAN AND OXB
CN = OB (given)
CA = Ox (given)
ANGLE CAN = ANGLE OXB
therfore CAN = OXB (RHS)
Angle NCA = angle BOX (cpct)
but these are equal alternate angles
Therefore CN is parallel to OB
AN=BX (CPCT)
AX=AX (COMMON)
BA+AX = AX + NX
THEREFORE BA = XN