Question

please prove fast...​

Answer 1

Answer:

Prove fast ?????????......

Answer 2

Step-by-step explanation:

by using..

1 + tan²A = sec²A

and..

tan²A = sec²A - 1

...

taking LHS

= 2-tan²A/1+tan²A

= 2-(sec²A-1)/sec²A

= 2-sec²A+1/sec²A

= 3-sec²A/sec²A

= 3/sec²A - sec²A/sec²A

now we know...

1/sec²A = cos²A

so...using that

LHS = 3cos²A - 1

and

according to question

RHS = 3cos²A-1

so

LHS = RHS

hence proved...

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