Math, asked by rajeshluhach2366, 1 year ago

please prove it bro​

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Answers

Answered by spiderman2019
1

Answer:

Step-by-step explanation:

SInA/SecA+TanA - 1   + CosA/CosecA+CotA - 1

= SinA/1/CosA + SinA/CosA - 1  + CosA/1/SinA + CosA/SinA - 1

= SinACosA/1+SinA - CosA  + SinACosA/1 + CosA - SinA

= SinACosA[1 /1 + (SinA-CosA)   + 1/1 - (SinA-CosA)]

= SinACosA[1 - (SinA-CosA) + 1 + (SinA-CosA)  / 1 - (SinA-CosA)²]

= 2SinACosA/1 - Sin²A - Cos²A+ 2SinACosA

= 2SinACosA/Cos²A-Cos²A+ 2SinACosA

= 2SinACosA/2SinACosA

= 1

= R.H.S

Hence Proved.

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