Question

Please prove this!!
$\frac{cos2x \: sinx \: + \: cos 6x \: sin 3x}{sin2x \: sinx \: + \: sin6x \: sin 3x} = cot \: 5x$
​

Answer 1

Answer:

The formula to use is sinA+sinB=2sin((A+B)/2)cos((A-B)/2)

sin(x) + sin(3x) = 4 sin(x) cos^2(x)

2sin((x+3x)/2)cos((3x-x)/2)=2sin2xcosx=4sinxcosxcosx=4sinxcos2x

Answer 2

Answer:

Hope its helps you very much