Question

please provide answer to the above question ..
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Answer 1

$We\:know\:the\:formula\:for\:n^{th}\:second$

$\Rightarrow \red{\boxed{s_{n} = u + \dfrac{1}{2}a(2n - 1)}}$

$\rightarrow u = Initial\:velocity$

$\rightarrow a = Acceleration due to gravity</p><p>$

$\rightarrow n = Time$

$s_{n}\:at\:8sec = u + \dfrac{1}{2}a{2(8) - 1)}$

$255 = u + \dfrac{15}{2}a [Equation (1)]$

$s_{n}\:at\:13sec = u + \dfrac{1}{2}a{2(13) - 1)}</p><p>$

$225 = u + \dfrac{25}{2}a [Equation (2)]$

$\text{On subtracting the two equations,}$

$255 = u + \dfrac{15}{2}a - 225 = u + \dfrac{25}{2}a = -6$

$a = -6$

$\text{On putting the value in the equation 1,we get}$

$255 = 2u + \dfrac{15}{2} \times -6$

$It\:will\:give\:the\:value\:of\:u\:as\:300cms^{-1}</p><p>$

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$\mathcal{BE\:\:\:BRAINLY}$