Question

Please provide me the answer of above question

Answer 1

Hey frnd....



Thanks for asking this question.
Here is your answer.....

✨Quadratic Equations✨


The solution is in the attachment.


Hope this would help you.

Answer 2

(b square )-4ac=0
[2(k-1)]+4(k)(4)=0
4(k square+1-2k)+16k =0
(4ksquare+4-8k)+16k =0
4k square +4 +8k =0
4k(k+2) + 4 =0
4k +4 =0
4k=-4
k=-4÷4
k=1