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☑PROPER SOLUTION REQD.
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Given Equation is p(x) = x^2018.
Given that it is divided by x^2 - 1.
= > x^2 - 1
= > x^2 - 1^2
We know that a^2 - b^2 = (a + b)(a - b).
= > (x + 1)(x - 1).
Now,
We know that Dividend = Divisor * Quotient + Remainder.
x^2018 = Divisor * (x + 1)(x - 1) + ax + b
Substitute x = 1, we get
1^2018 = 0 + a(1) + b
1 = 0 + a + b
a + b = 1 ------------ (1)
Substitute x = -1, we get
(-1)^2018 = 0 + a(-1) + b
1 = -a + b
-a + b = 1 ------------- (2)
On solving (1) &(2), we get
a + b = 1
-a + b = 1
------------------
2b = 2
b = 1
Substitute b = 1 in (1), we get
a + b = 1
a + 1 = 1
a = 1 - 1
a = 0.
Remainder = ax + b
= 0 * x + 1
= 0 + 1
= 1.
Therefore:
|a| - |b| = |0| -|1|
= -1.
Hope this helps!
Given that it is divided by x^2 - 1.
= > x^2 - 1
= > x^2 - 1^2
We know that a^2 - b^2 = (a + b)(a - b).
= > (x + 1)(x - 1).
Now,
We know that Dividend = Divisor * Quotient + Remainder.
x^2018 = Divisor * (x + 1)(x - 1) + ax + b
Substitute x = 1, we get
1^2018 = 0 + a(1) + b
1 = 0 + a + b
a + b = 1 ------------ (1)
Substitute x = -1, we get
(-1)^2018 = 0 + a(-1) + b
1 = -a + b
-a + b = 1 ------------- (2)
On solving (1) &(2), we get
a + b = 1
-a + b = 1
------------------
2b = 2
b = 1
Substitute b = 1 in (1), we get
a + b = 1
a + 1 = 1
a = 1 - 1
a = 0.
Remainder = ax + b
= 0 * x + 1
= 0 + 1
= 1.
Therefore:
|a| - |b| = |0| -|1|
= -1.
Hope this helps!
siddhartharao77:
if wrong..delete directly
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