Question

please provide solution

Answer 1

Given 3tanA +4 = 0 => tanA = -4/3 = -tan 53°
as we know tan(π-x) = tan(2π-x) = -tanx
so putting 53° in eqn we get
tanA = tan(π-53°) = tan(2π-53°)
tanA = tan 127° = tan 307°
Therefore you have two solutions
1. 2cot127°+5cos127°+sin127° = -37/10
2.2cot307°+5cos307°+sin307° = 7/10
I think these are the two answers -37/10 in range b/w π/2 to π and 7/10 in range b/w 3π/2 to 2π.