Question

please provide solution

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Answer 1

solution:

By using Pythagoras theorem we can calculate the distance between OA.

Here,
In ∆EFO ,

${eo}^{2} = {ef}^{2} + {fo}^{2} \\ = > eo = \: \sqrt{ {ef}^{2} + {fo}^{2} }$
Now, In ∆AEO,
${ao}^{2} = {ae}^{2} + {eo}^{2} \\ {ao}^{2} = {ae}^{2} + { \sqrt{ {ef}^{2} + {fo}^{2} } }^{2} \\ = > {ao}^{2} = {ae}^{2} + {ef}^{2} + {fo}^{2} \\ = > ao = \sqrt{ {ae}^{2} + {ef}^{2} + {fo}^{2} }$
___________________
Amrit

Answer 2

solution:

By using Pythagoras theorem we can calculate the distance between OA.

Here,

In ∆EFO ,

\begin{lgathered}{eo}^{2} = {ef}^{2} + {fo}^{2} \\ = > eo = \: \sqrt{ {ef}^{2} + {fo}^{2} }\end{lgathered}

eo

2

=ef

2

+fo

2

=>eo=

ef

2

+fo

2

Now, In ∆AEO,

\begin{lgathered}{ao}^{2} = {ae}^{2} + {eo}^{2} \\ {ao}^{2} = {ae}^{2} + { \sqrt{ {ef}^{2} + {fo}^{2} } }^{2} \\ = > {ao}^{2} = {ae}^{2} + {ef}^{2} + {fo}^{2} \\ = > ao = \sqrt{ {ae}^{2} + {ef}^{2} + {fo}^{2} }\end{lgathered}

ao

2

=ae

2

+eo

2

ao

2

=ae

2

+

ef

2

+fo

2

2

=>ao

2

=ae

2

+ef

2

+fo

2

=>ao=

ae

2

+ef

2

+fo

2

___________________

Amrit

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