Question

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Answer 1

Multiplying 2 on numerator and denominator and applying 2cosAsinB and 2sinAcosB identity on numerator and applying 2cosAcosB and 2sinAsinB identity on denominator

{sin12A-sin(-6A)}-{sin6A+sin(-4A)}
__________________________
cos6A+cos4A-cos6A-cos12A

Since sin6A will be cut from the numerator and cos6A from denominator

sin12A-sin4A
___________
cos4A-cos12A
Appying sinC-sinD and cosC-cosD identity

2 sin4A.cos8A
____________
2sin8A.sin4A

= cos8A
_____. = cot8A
sin8A

I hope it will help you
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Answer 2

Hope you understand .......