Question

Please refer the attachment​

Answer 1

Answer:

Here, ∠CBA= 80°

Now, DC and AB are parallel and let CB be the transversa, hence ∠CDB and ∠CBA are alternate interior angle, hence x = 80°

Now, sum of all angles of a quadrilateral is always 360° Hence ∠A + ∠B + ∠C + ∠D = 360°, hence 120+80+80+y=360. ∴ y= 80°

Answer 2

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