Question

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Answer 1

in triangle ANO and triangle CMO,
Angle N=Angle M=90
Angle AON = Angle COM (Vertically opposite angle)
therefore triangle ANO is Similar to triangle CMO by AA test
therefore AN/CM=AO/CO(CSST)
ar(triangleADB)/ar(triangleCDB)=1/2*AN*BD/1/2*CM*BD
=AN/CM=AO/CO
hence proved
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