Math, asked by Gohulsundar, 10 months ago

please say answer.
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Answered by tanvichhabra29
0

Answer: K.E of ball before collision with sand = P.E at 50m hieght.

Work done by resistive force=P.E at 50m hieght.

F.d = mg*50

F=5*10*50/-1 negative sign due to

displacement in sand is opposite to the resistance (F).

F=2500N

Velocity before collision w1k sand is v =√2g*50

N= √1000=31.62m/s

Change in momentum= mv

F∆t=5*31.62

t=0.0632 sec.

Step-by-step explanation:

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