please say answer.
i will mark as brain list
Attachments:
Answers
Answered by
0
Answer: K.E of ball before collision with sand = P.E at 50m hieght.
Work done by resistive force=P.E at 50m hieght.
F.d = mg*50
F=5*10*50/-1 negative sign due to
displacement in sand is opposite to the resistance (F).
F=2500N
Velocity before collision w1k sand is v =√2g*50
N= √1000=31.62m/s
Change in momentum= mv
F∆t=5*31.62
t=0.0632 sec.
Step-by-step explanation:
Similar questions