Question

please say me the answer of this

please say correct answer .

l will mark as brainlist . ​

Answer 1

Answer:

$given \: that \: \\ \frac{ {243}^{0.13} \times {243}^{0.07} }{ {7}^{0.25} \times {49}^{0.075} \times {343}^{0.2} } = ( { \frac{7}{3}) }^{2x} \\ 243 \: can \: be \: written \: as \: 243 = {3}^{5} \\ 49 \: = {7}^{2} \: and \: 343 \: = {7}^{3} \\ \frac{ ({ {3}^{5}) }^{0.13} \times ({ {3}^{5}) }^{0.07} }{ {7}^{0.25} \times ({ {7}^{2}) }^{0.075} \times ({ {7}^{3})}^{0.2} } = ( { \frac{7}{3}) }^{2x} \\ we \: know \: that \: \\ {a}^{m} \times {a}^{n} = {a}^{(m + n)} \\ \: and \: \: \: ( { {a}^{m}) }^{n} \: = \: {a}^{mn} \\ \\ \frac{ {3}^{(0.65 + 0.35)} }{ {7}^{(0.25 + 0.150 + 0.6)} } = \: ( { \frac{7}{3}) }^{2x} \\ \\ \frac{ {3}^{1.00} }{ {7}^{1.0} } \: = \: \: ( { \frac{7}{3}) }^{2x} \\ \\ \frac{3}{7} = \: \: ( { \frac{7}{3}) }^{2x} \: \\ ({ \frac{7}{3}) }^{ - 1} \: = \: \: \: ( { \frac{7}{3}) }^{2x} \\ since \: {a}^{ - n} = \frac{1}{ {a}^{n} } \\ we \: know \: that \: \\ if \: bases \: are \: equal \: then \: exponents \: must \: be \: equal \\ = > \: - 1 \: = \: 2x \\ = > x = \frac{ - 1}{2}$

Step-by-step explanation:

x = -1/2

Answer 2

SOLUTION :

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