Question

please say me this question please tommrow is my maths exam

Answer 1

hey mate this is ur ans

Answer 2

$x {}^{2} + (a + 1)x + b$

2 and -3 are zeroes of the polynomial.Then it must satisfy the equation.

$(2) {}^{2} + (a + 1)2 + b = 0$

$4 + 2a + 2 + b = 0$

$2a + b = - 6 \: \: \: \: \: \: \: eq1$

$( - 3) {}^{2} + (a + 1)( - 3) + b = 0$
$9 - 3a - 3 + b = 0$

$- 3a + b = - 6$
Now take - common

$3a - b = 6 \: \: \: \: \: \: \: \: eq2$

On adding eq1 and eq2

$5a = 0$

$a = 0$

Put a in eq 2

3(0) - b = 6

b = -6

Hence ,. a = 0 and b= -6


Thanks