Question

☝☝please see the picture and answer me ​

Answer 1

Answer:

4m

Step-by-step explanation:

one rope = 8m

other rope = 12m

Factor of 8 : 1,2,4,8

Factor if 12 : 1,2,3,4,6 12

Common factor of 8 and 12 : 1,2,4

HCF of 8 and 12 = 4

therefore max possible length of each piece3of rope of same length = 4m

thus the max possible length of eack piece of rope is 4m

hope u got it....