☝☝please see the picture and answer me
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Answer:
4m
Step-by-step explanation:
one rope = 8m
other rope = 12m
Factor of 8 : 1,2,4,8
Factor if 12 : 1,2,3,4,6 12
Common factor of 8 and 12 : 1,2,4
HCF of 8 and 12 = 4
therefore max possible length of each piece3of rope of same length = 4m
thus the max possible length of eack piece of rope is 4m
hope u got it....
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