please send answer for 14th question asap
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Am is perpendicular to bc.. N bc n od r parallel... So angle aod is 90°... Thn aod is at centre and abm is at circumference... So abm is 45°... Then using angle sum prop in triangle abm we get x = 45°
ayushigupta2001:
Then od is parallel to bc.. So angle cod is also 50°..
Cod is at centre but cbd at circumference.. So y is 25°
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y will get all the answer in study material or study ranker and CBSE info bank
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