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Given angles of hexagon are x + 10,2x + 20,2x - 20,3x - 50,x + 40 and x + 20.
We know that sum of interior angles of a hexagon = 720.
x + 10 + 2x + 20 + 2x - 20 + 3x - 50 + x + 40 + x + 20 = 720
10x + 20 = 720
10x = 720 - 20
10x = 700
x = 70.
Hence, x = 70.
Hope this helps!
We know that sum of interior angles of a hexagon = 720.
x + 10 + 2x + 20 + 2x - 20 + 3x - 50 + x + 40 + x + 20 = 720
10x + 20 = 720
10x = 720 - 20
10x = 700
x = 70.
Hence, x = 70.
Hope this helps!
siddhartharao77:
Thanks Tharani
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Hii I am arpit
(x+10)+(2x+20)+(2x-20)+(3x-50)+(x+40)+(x+20)=540
x+2x+2x+3x+x+x=540-10-20+20+50-40-20
10x=520
x=520/10
x=52
I think it will help u
(x+10)+(2x+20)+(2x-20)+(3x-50)+(x+40)+(x+20)=540
x+2x+2x+3x+x+x=540-10-20+20+50-40-20
10x=520
x=520/10
x=52
I think it will help u
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