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Hi there !!
Here your answer
Given,
to factorise 2x³ + 54
Taking 2 as common factor in 2x³ + 54 , we have,
2(x³ + 27)
It can be seen that x³+27 is in the form of the algebraic identity a³+ b³ = (a+b)(a²-ab+b²)
Also,
when x is cubed , it is written as x³
and when 3 is cubed , it is written as 27
So,
2(x + 3)(x² - x(3) + 3²)
= 2(x + 3)(x² - 3x + 9) is the factorised Answer
Here your answer
Given,
to factorise 2x³ + 54
Taking 2 as common factor in 2x³ + 54 , we have,
2(x³ + 27)
It can be seen that x³+27 is in the form of the algebraic identity a³+ b³ = (a+b)(a²-ab+b²)
Also,
when x is cubed , it is written as x³
and when 3 is cubed , it is written as 27
So,
2(x + 3)(x² - x(3) + 3²)
= 2(x + 3)(x² - 3x + 9) is the factorised Answer
Anonymous:
:-)
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