Question

two charges Q1 and Q2 are separated by a distance D if the distance is doubled the forces

Answer 1

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Answer 2

Given:

Two Charges Q1 and Q2

Distance between charges = D

To Find:

Force when Distance is doubled

Solution:

We Know,

force between two charges (F) =  $(\frac{Q1 * Q2}{D^{2} } )K$

now, Distance is doubled i.e D=2D

F = $(\frac{Q1 * Q2}{(2D)^{2} } )K$

F = $(\frac{Q1 * Q2}{4D^{2} } )K$

F = $(\frac{Q1 * Q2}{D^{2} } )K *\frac{1}{4}$

F = $\frac{F}{4}$

So, the Force gets reduced by 1/4th of the initial force.