Question

please send me answer of this it is urgent​

Answer 1

Answer:

3/8

Step-by-step explanation:

n(s)= { HHH, HTH, HHT, HTT,

TTT ,THT, TTH, THH }

n(s)= 8

n(a)= getting only 2 heads

= 3

p(a)= n(a)/n(s)

=3/8

Answer 2

Three coins are tossed together.

So, Possible outcomes ={HHH, TTT, HHT, HTH, HTT, TTH, THT, THH}

Total number of outcomes =8

Favourable outcomes= HHT, HTH, THH.

Number of favourable outcome= 3

Therefore,

Probability of getting exactly two heads= 3/8

hope it will help u ✨☺️