Question

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Answer 1

$\bold{Answer}$

x= 1 and y=0

$\bold{Solution}$

Look in attachment

Answer 2

$( { \frac{1 + i}{1 - i} )}^{200} \\ { \frac{(1 + i)(1 + i)}{(1 - i)(1 + i)}}^{200} \\ \\ \ { (\frac{ {(1 + i)}^{2} }{2} })^{200} \: \: \: \: \: \: \: \: \: \: \: \: ( {i}^{2} = - 1) \\ \\ \frac{1 + {i}^{2} + 2i}{2} power \: 200 \\ = {i}^{200} \\ \\ = {i}^{0} \\ = 1$

x=1 and y=0

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