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1.
∆ABC is a right angled ∆ at C
so,
AngleC=90°
now,
In∆ABC,
by angle sum property of a ∆
angleA+angleB+AngleC=180°
angleA+angleB+90°=180°
angleA+angleB=90°
therefore,
cos(A+B)=cos90
2.
volume of 1cube=125cm³
side³=125
side=5cm
now,
length of cuboid=5+5+5
=15cm
breadth=5cm
height=5cm
SA of cuboid=2(lb+bh+hl)
=2(15×5+5×5+5×15)
=2(75+25+75)
=2×175
=350cm²
hope this answers will help you.
∆ABC is a right angled ∆ at C
so,
AngleC=90°
now,
In∆ABC,
by angle sum property of a ∆
angleA+angleB+AngleC=180°
angleA+angleB+90°=180°
angleA+angleB=90°
therefore,
cos(A+B)=cos90
2.
volume of 1cube=125cm³
side³=125
side=5cm
now,
length of cuboid=5+5+5
=15cm
breadth=5cm
height=5cm
SA of cuboid=2(lb+bh+hl)
=2(15×5+5×5+5×15)
=2(75+25+75)
=2×175
=350cm²
hope this answers will help you.
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