Question

please send me the answers to question no 19 to 22

Answer 1

(19)secθ-tanθ=4...................(1)

sec²θ-tan²θ=1
(secθ-tanθ)(secθ+tanθ)=1
secθ+tanθ=1/4................(2)

adding (1) & (2)
secθ=4-1/4
secθ=17/8
secθ=1/cosθ
cosθ=8/17

(21)
i)0/44
ii)26/44
iii)18/44

(22)
Area of segment = θ/360*Πr²-r²sinθ/2cosθ/2
                           =120/360 * 22/7 * 14*14 - 14*14 * sin60 cos60
                           =616/3-49√3


NOTE:I cnanot give the answer of 20 because it need time as well as daigram