Question

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Answer 1

Answer:

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Answer 2

Answer:

Let us consider ∠A=4x and

∠D=5x

Since, AB∣∣DC

So,

∠A+∠D=180o

Substituting the value of angle A and D, we get

4x+5x=180%o

9x=180o

x=20o

Now

∠A=4x=4×20o

=80o

∠D=5x=5×20o

=100o

Similarly since, AB∣∣DC

∠B+∠C=180o

7x+5o=180o

7x=180o−5o

7x=175o

We get,

x=25o

∠B=3x−15o=3×25o−15o

=75o−15o

=60o nad

∠C=4x+20o=4x×25