please send the answer of this if anyone knows eight question .
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Let one part be x
∴ The other part is (184 – x)
One-third of x = (x/3)
One-seventh of other part
Given that one-third of one part exceeds one-seventh of other part by 8.
⇒ 7x = 3(240 – x)
⇒ 7x = 720 – 3x
⇒ 10x = 720
∴ x = 72
Hence the two parts 72 and 112.
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Let the first part be a
Second part = 184 - a
According to question
a/3 - (184-a) / 7 = 8
=> [ 7a - 3(184 - a)] /21 = 8
=> 7a + 3a - 552 = 8 * 21
=> 10a - 552 = 168
=> 10a = 168 + 552
=> 10a = 720
=> a = 72
First part = 72
Second part = 112
Second part = 184 - a
According to question
a/3 - (184-a) / 7 = 8
=> [ 7a - 3(184 - a)] /21 = 8
=> 7a + 3a - 552 = 8 * 21
=> 10a - 552 = 168
=> 10a = 168 + 552
=> 10a = 720
=> a = 72
First part = 72
Second part = 112
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