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Answer:
Given:
A circuit having 3 resistors have been provided.
To find:
1. Net resistance
2. Potential difference between "A and B" and "B and C"
3. Current through PQ AND AC .
Calculation:
1st part:
2 ohm and 4 ohm are in series
Hence total resistance is 4+2 = 6 ohm.
And these are parallel to 3 ohm.
Effective resistance = (3×6)/(3+6)
=> R effective = 2 ohm
2nd part:
Current through AC branch
= V/R
= 6/(4+2)
= 6/6
= 1 ohm
So potential difference along A and B
= I × R"
= 1 × 2
= 2 volts.
Similarly, potential drop along B and C
= I × R'
= 1 × 4
= 4 volts
3rd part:
Current through AC
= V/R
= 6/6
= 1 amp.
Similarly, current through PQ
= V/R
= 6/3
= 2 amp.
Q. 1)CALCULATE EFFECTIVE RESISTANCE
2 Ω and 4 Ω are connect in series :-
R s=R1+R2........(1)
.°. 2+4=
and these are connect in parallel to 3Ω.
effective resistance=/
.°.effective resistance=
Q. 2)CALCULATE THE POTENTIAL DIFFERENCE BETWEEN POINTS A AND B AND POINTS B AND C.
Con. 1) current through AC branch.
= /
=
NOW,
CON. 2)CALCULATE POTENTIAL DIFFERENCE BETWEEN A AND B.
=Í ×R1.....(from 1.)
=1×2
=
THEN,
CALCULATE POTENTIAL DIFFERENCE BETWEEN B AND C.
=Í ×R2......(from 1)
=1×4
=
Q. 3)CALCULATE CURRECT THROUGH BRACH AC AND PQ.
CON.1)CURRENT THROUGH AC.
= /
=
CON. 2)CURRENT THROW PQ.
=V/R.
= /
=