Question

Please share the correct solution...
It's urgent..​

Answer 1

this is the correct answer ok

Answer 2

Answer:

By Pythagoras theorem,

AC^2 = AD^2 + DC ^2

(13)^2 = AD^2 + (5)^2

169 = AD^2 + 25

AD^2 = 169 - 25

AD^2 = 144

AD = 12

(i) tan x = perpendicular/base

= CD/AD

= 5/12

Again by Pythagoras theorem,

AB^2 = AD^2 + BD^2

AB^2 = (12)^2 + (16)^2 {BD = BC - DC}

AB^2 = 144 + 256

AB^2 = 400

AB = 20

(ii) cos y = base/hypotenuse

= BD/AB

= 16/20

= 0.8

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