Question

Please show me this math. please. The power is -3/4​

Answer 1

Answer:

the qwetion that you have send is blur i cant understand

Answer 2

Step-by-step explanation:

$(\frac{256a^{16}}{81b^{4}})^{\frac{-3}{4}}\\\\=((\frac{4a^{4}}{3b})^{4})^{\frac{-3}{4}}\\\\= (\frac{4a^{4}}{3b})^{(4*\frac{-3}{4})}\\\\= (\frac{4a^{4}}{3b})^{-3}\\\\=(\frac{3b}{4a^{4}})^{3}\\\\=\frac{27b^{3}}{64a^{12}}$

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